A 12 5 G Sample Of Granite Initially At 82 0

A 12 5 g sample of granite initially at 82 degrees celsius is immersed into 25 g of water initially at 22 degrees celsius.

A 12 5 g sample of granite initially at 82 0. For water cs 4 18 j oc g and for granite cs 0 790 j oc g. Let s say we want to cool the sample down by 3 degrees. Then δt 3 k. A 12 5 g sample of granite initially at 82 0 c is immersed into 25 0 g of water initially at 22 0 c.

What is the final temperature of both substances when they reach thermal equilibrium. C 15 7 0 c. A 12 5 g sample of granite initially at 82 0oc is immersed into 25 0 g of water initially at 22 0oc. O c and for granite c 0 790 j g.

B 1 55 10 3 0 c. What is the final temperature of both substances when they reach thermal equilibrium. For water c s 4 18 j g c and for granite c s 0 790 j g c a. A 12 0 g sample of granite initially at 84 0 c is immersed into 29 0 g of water initially at 21 0 c.

What is the final temperature of both substances when they reach thermal equilibrium. What is the final temperature of both substances when they reach thermal equilibrium. In our example it will be equal to c 63 000 j 5 kg 3 k 4 200 j. For water specific heat 4 18 j g degrees celsius and for granite specific heat 0 79 j g degrees celsius.

A 12 5 g sample of granite initially at 82 0 o c is immersed into a 25 0 g of water initially at 22 0 o c. A 12 5 g sample of granite initially at 82 0 c is immersed in 25 0 g of water initially at 22 0 c. A 12 5 g sample of granite initially at 82 0 0 c is immersed into 25 0 g of water initially at 22 0 0 c. What is the final temperature of both substances when they reach thermal equilibrium.

The answer to a 12 5 g sample of granite initially at 82 0 0c is immersed into 25 0 g of water initially at 22 0 0c. Calculate specific heat as c q mδt. For water cs 4 18j g c and for granite cs 0 790j g c express your answer using three significant figures. 1 55 10 3 c c.

We will assume m 5 kg. A 52 0 0 c. You can also go to advanced mode to type the initial and final values of temperature manually. D 27 2 0 c.

What is the final temperature of both substances when they reach thermal equilibrium. Determine the mass of the sample. What is the final temperature of both substances when they reach thermal equilibrium. Granite is 0 79 j g c.

For water c s 4 18 j g 0 c and for granite c s 0 790 j g 0 c.